Question on: WAEC Mathematics - 2006
In the diagram, PR is a diameter of the circle centre O. RS is a tangent at R and QPR = 58o. Find < QRS
A
112o
B
116o
C
122o
D
148o
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Correct Option: C
PRQ = 90 - 58 = 32o(angle in a semi-circle)
Since PRS = 90o(radius angular to tangent)
QRS = 90 + 32
= 122o
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